作业

// func1 函数：返回 c * (a + b)
int func1(int a, int b, int c) {
    return c * (a + b);
}

// func2 函数：调用 func1 函数，传递 (x + 2), (y + 1), (x + y)
int func2(int x, int y) {
    return func1(x + 2, y + 1, x + y);
}



int func(int n) {
    if (n <= 1) {
        return 1;  // 基本情况，当 n <= 1 时返回 1
    }
    return func(n - 1) + n * n;  // 递归计算 func(n-1) + n^2
}




int func(int n) {
    if (n <= 0) {
        return 1;
    } else {
        int half = n / 2;
        return 3 + n + func(half);
    }
}




long func(long a, long b, int c, int d, short e, short f, char g, char h) {
    // 步骤 1: 计算 a + b
    long sum_ab = a + b;
    
    // 步骤 2: 计算 c + d
    long sum_cd = c + d;
    
    // 步骤 3: 计算 (a + b) * (c + d)
    long product_ab_cd = sum_ab * sum_cd;
    
    // 步骤 4: 计算 e + f
    int sum_ef = e + f;
    
    // 步骤 5: 计算 (a + b) * (c + d) * (e + f)
    long product_ab_cd_ef = product_ab_cd * sum_ef;
    
    // 步骤 6: 计算 g + h
    int sum_gh = g + h;
    
    // 步骤 7: 计算 (a + b) * (c + d) * (e + f) * (g + h)
    long result = product_ab_cd_ef * sum_gh;
    
    return result;
}





void func1(int *p1, int *p2) {
    int temp1 = *p1;
    int temp2 = *p2;
    *p1 = temp1 + temp2;  // *p1 = *p1 + *p2
    *p2 = temp1 - temp2;  // *p2 = *p1 - *p2
}

int func2(int a, int b) {
    int x = a, y = b;
    func1(&x, &y);  // 调用 func1 修改 x 和 y
    return x * x + y * y;  // 计算 a^2 + b^2
}